Breder.org Software and Computer Engineering

How to Program a Reverse Polish Notation (RPN) Calculator in C

We are going through the steps of developing a stack-based RPN calculator in C.

Reading input

First the program needs to read the input from the terminal, one line at a time:

#include <assert.h>
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <readline/readline.h>

int main() {
	while (true) {
		char* c = readline("> ");
		assert(c != NULL);
		printf("Your command: %s\n", c);
		free(c);
	}
}

You might need to first install the readline library for development. This library is maintained by the GNU project and provides -- among other things -- a nicer handling of the keyboard arrow keys.

On Debian Linux, the development library is available as the libreadline-dev package.

sudo apt install libreadline-dev

Filly, when compiling, we must link the readline library by passing a command-line argument.

gcc -o rpn1 rpn1.c -lreadline

Parsing Positive Integer Numbers

A simple function to parse a string of ASCII digits into an integer number is shown below.

int parse_int(char* s) {
	int acc = 0;
	char* p = s;
	while (*p != '\0' && *p != '\r' && *p != '\n') {
		assert((*p) >= '0' && (*p) <= '9');
		acc *= 10;
		acc += (*p) - '0';
		p++;
	}
	return acc;
}

Note that it has two main flaws or limitations:

We can adapt main so that we can test that the function works correctly for a few numbers:

int main() {
	while (true) {
		char* c = readline("> ");
		assert(c != NULL);
		int n = parse_int(c);
		printf("Your number: %d\n", n);
		free(c);
	}
}

Although the output is exactly the same as the step before, there's a very critical disticion: Now the number is being held as an integer in the n variable, instead of a sequence of ASCII digits in the c variable.

The Stack Data Structure

The stack is central to how a RPN calculator works.

By inputting numbers, we push those numbers into the stack.

By inputting operators, we pop numbers from the stack and push back the result.

For example:

stack: [ ]
> 123
stack: [ 123 ]
> 456
stack: [ 123 456 ]
> +
stack: [ 579 ]

Let's setup some storage for the stack, implement the push and pop operations and a printing routine.

#define STACK_SIZE 128
int stack[STACK_SIZE];
int stack_i = 0;

void stack_push(int n) {
	assert(stack_i < STACK_SIZE);
	stack[stack_i] = n;
	stack_i++;
}

int stack_pop() {
	assert(stack_i > 0);
	stack_i--;
	return stack[stack_i];
}

int stack_print() {
	printf("stack: [");
	for (int i = 0; i < stack_i; i++) {
		printf(" %d", stack[i]);
	}
	printf(" ]\n");
}

Finally, let's adjust main to push every new number typed in into the stack.

int main() {
	while (true) {
		stack_print();
		char* c = readline("> ");
		assert(c != NULL);
		int n = parse_int(c);
		stack_push(n);
		free(c);
	}
}

Performing Arithmetic Operations

For this final step, let's make the calculator, well, calculate.

We start by define a few operations and matching strings to either one of the possible operations or to a sentinel “invalid” operation;

#define OP_INVALID -1
#define OP_ADD 1
#define OP_SUB 2
#define OP_MUL 3
#define OP_DIV 4
#define OP_REM 5

int parse_op(char* str) {
	if (strcmp(str, "+") == 0) return OP_ADD;
	if (strcmp(str, "-") == 0) return OP_SUB;
	if (strcmp(str, "*") == 0) return OP_MUL;
	if (strcmp(str, "/") == 0) return OP_DIV;
	if (strcmp(str, "%") == 0) return OP_REM;
	return OP_INVALID;
}

Performing the operation itself requires manipulating the stack. We need to: 1) pop the operands in the correct order; 2) perform the operation; and 3) push back the result into the stack. The code goes as follows:

void perform_op(int op) {
	int right = stack_pop();
	int left = stack_pop();
	int result = 0;
	switch (op) {
	case OP_ADD: result = left + right; break;
	case OP_SUB: result = left - right; break;
	case OP_MUL: result = left * right; break;
	case OP_DIV: result = left / right; break;
	case OP_REM: result = left % right; break;
	default: assert(!"Invalid op value");
	}
	stack_push(result);
}

Finally, we adjust the main function to first try to interpret the input as an operator.

If it doesn't match a supported operator, we assume it is an integer and push it into the stack.

int main() {
	while (true) {
		stack_print();
		char* c = readline("> ");
		assert(c != NULL);
		int op = parse_op(c);
		if (op == OP_INVALID) {
			int n = parse_int(c);
			stack_push(n);
		} else {
			perform_op(op);
		}
		free(c);
	}
}

The Full Program

The source code is available below. The following improvements could be made and are left as an exercise to the reader:

// SPDX-License-Identifier: MIT
// 2023 Victor Breder

#include <assert.h>
#include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <readline/readline.h>

int parse_int(char* s) {
	int acc = 0;
	char* p = s;
	while (*p != '\0' && *p != '\r' && *p != '\n') {
		assert((*p) >= '0' && (*p) <= '9');
		acc *= 10;
		acc += (*p) - '0';
		p++;
	}
	return acc;
}

#define STACK_SIZE 128
int stack[STACK_SIZE];
int stack_i = 0;

void stack_push(int n) {
	assert(stack_i < STACK_SIZE);
	stack[stack_i] = n;
	stack_i++;
}

int stack_pop() {
	assert(stack_i > 0);
	stack_i--;
	return stack[stack_i];
}

int stack_print() {
	printf("stack: [");
	for (int i = 0; i < stack_i; i++) {
		printf(" %d", stack[i]);
	}
	printf(" ]\n");
}

#define OP_INVALID -1
#define OP_ADD 1
#define OP_SUB 2
#define OP_MUL 3
#define OP_DIV 4
#define OP_REM 5
int parse_op(char* str) {
	if (strcmp(str, "+") == 0) return OP_ADD;
	if (strcmp(str, "-") == 0) return OP_SUB;
	if (strcmp(str, "*") == 0) return OP_MUL;
	if (strcmp(str, "/") == 0) return OP_DIV;
	if (strcmp(str, "%") == 0) return OP_REM;
	return OP_INVALID;
}

void perform_op(int op) {
	int right = stack_pop();
	int left = stack_pop();
	int result = 0;
	switch (op) {
	case OP_ADD: result = left + right; break;
	case OP_SUB: result = left - right; break;
	case OP_MUL: result = left * right; break;
	case OP_DIV: result = left / right; break;
	case OP_REM: result = left % right; break;
	default: assert(!"Invalid op value");
	}
	stack_push(result);
}

int main() {
	while (true) {
		stack_print();
		char* c = readline("> ");
		assert(c != NULL);
		int op = parse_op(c);
		if (op == OP_INVALID) {
			int n = parse_int(c);
			stack_push(n);
		} else {
			perform_op(op);
		}
		free(c);
	}
}

Compilation instructions:

# sudo apt install libreadline-dev
gcc -o rpn rpn.c -lreadline

Sample session when using the finished program:

stack: [ ]
> 60
stack: [ 60 ]
> 30
stack: [ 60 30 ]
> +
stack: [ 90 ]
> 5
stack: [ 90 5 ]
> /
stack: [ 18 ]
>